A person takes a loan on compound interest and returns it in $2$ equal installments . If the rate of interest is $10$ % per annum and the yearly installment is Rs $1682$ . Find the interest charged (approximately) with first installment.

Rs.

202

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Rs.

192

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Rs.

92

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Rs.

292

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Solution

The correct option is D Rs. $292$
$P = \frac{A}{(1 + \frac{R}{100})^{n}}$
$⟹ \frac{1682}{(1 + \frac{10}{100})^{1}}$ $+ \frac{1682}{(1 + \frac{10}{100})^{2}}$
$⟹ 1592.09 + 1390.08 = 2919.17 \approx 2920$
$⟹ A_{1} = 2920 (1 + \frac{10}{100}) = 3212$
$C I = A_{1} - P = 3212 - 2920 = R s .292$

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A person takes a loan on compound interest and returns it in 2 equal installments . If the rate of interest is 10% per annum and the yearly installment is Rs 1682. Find the interest charged (approximately) with first installment.

The correct option is D Rs. 292P=A(1+R100)n⟹1682(1+10100)1+1682(1+10100)2⟹1592.09+1390.08=2919.17≈2920⟹A1=2920(1+10100)=3212CI=A1−P=3212−2920=Rs.292

A person takes a loan on compound interest and returns it in $2$ equal installments . If the rate of interest is $10$ % per annum and the yearly installment is Rs $1682$ . Find the interest charged (approximately) with first installment.

The correct option is D Rs. $292$
$P = \frac{A}{(1 + \frac{R}{100})^{n}}$
$⟹ \frac{1682}{(1 + \frac{10}{100})^{1}}$ $+ \frac{1682}{(1 + \frac{10}{100})^{2}}$
$⟹ 1592.09 + 1390.08 = 2919.17 \approx 2920$
$⟹ A_{1} = 2920 (1 + \frac{10}{100}) = 3212$
$C I = A_{1} - P = 3212 - 2920 = R s .292$