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Question

# A person throws vertically 10 balls per second with the same velocity. He throws a ball whenever the previous one is at its highest point. The height to which the balls rise is

A
10 m
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B
5 m
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C
5 cm
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D
10 cm
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Solution

## The correct option is C 5 cm10 balls are thrown per second. Time interval between two balls thrown =110 s This is the time that a ball takes to reach its highest point. Using first equation of motion v=u+at As the velocity of ball is 0 at its maximum height ⇒0=u−g(110) (By first equation of motion) ⇒u=g10 Height achieved by the balls is given by v2−u2=2aS ⇒02−(g10)2=2×(−g)h ⇒h=g2×102=0.05 m=5 cm The answer is (c)

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