wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A person traveling on a straight line moves with a uniform velocity v1 for a distance x and with uniform velocity v2 for the next equal time. The average velocity v is given by

A
v=v1+v22
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
v=v1v2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
v=v1v2v1+v2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
v=v1+v2v1v2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A v=v1+v22
As shown, the person travels from A to B through a distance S, where first part S1 is travelled in time t/2 and text S2 also in time t/2.
So, according to the condition : v1=S1t/2 and v2=S2t/2
Average velocity = TotaldisplacementTotaltimetaken=S1+S2t=v1t2+v2t2t=v1+v22

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon