A person travelling on a straight line moves with a uniform velocity v1 for some time and with uniform velocity v2 for the next equal time. The average velocity v is given by:
A
v=v1+v22
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
v=√v1v2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2v=1v1+1v2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1v=1v1+1v2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Av=v1+v22 Displacement during the velocity v1 will be x1=v1t
Displacement during the velocity v2 will be x2=v2t
Average velocity will be Displacementtime=x1+x2t+t=v1t+v2t2t=v1+v22