A person travels along a straight road for the first half time with a velocity, v1 and the second half time with a velocity, v2. Then the mean velocity ¯v is given by:
A
¯v=v1+v22
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B
2v=1v1+1v2
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C
¯v=√v1v2
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D
¯v=√v2v1
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Solution
The correct option is A¯v=v1+v22 For the first half time=t, velocity=v1, distance=s1=v1t For the second half time=t, velocity=v2, distance=s2=v2t Mean velocity =s1+s2t+t=v1t+v2t2t=v1+v22