A person travels from A to B at the speed of 120 km an hour and returns from B to A at the speed of 80 - km an hour. What is his average speed?

100 km/hr

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96 km /hr

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90 km /hr

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60 km /hr

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Solution

The correct option is B 96 km /hr
$L e t t h e d i s t a n c e b e x, t i m e t a k e n t o t r a v e l = \frac{x}{120}, t i m e t a k e n t o r e t u r n = \frac{x}{80}, a v e r a g e s p e e d = \frac{T o t a l d i s t a n c e}{t i m e t a k e n} = \frac{2 x}{\frac{x}{120} + \frac{x}{80}} = \frac{2 x * 240}{5 x} = 96 k m / h r$

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A person travels from A to B at the speed of 120 km an hour and returns from B to A at the speed of 80 - km an hour. What is his average speed?

The correct option is B 96 km /hrLetthedistancebex,timetakentotravel=x120,timetakentoreturn=x80,averagespeed=Totaldistancetimetaken=2xx120+x80=2x∗2405x=96km/hr