Question

A person walking towards north covers $4km$ and turns towards east and covers $3km$ in total times $5$ hours, then average velocity is

• A. $1kmph$
• B. $2kmph$
• C. $3kmph$
• D. $4kmph$

Answer 1

The correct option is A $1kmph$

Velocity is a $vector$ quantity so we need to deal with the $displacement$.

The displacement will be $vector$ sum of the distance in each direction.

As north and east are $perpendicular$ to each other so net displacement

will be $x=\sqrt{4^2+3^2+2\times 4\times 3Cos{90}^0}=5Km$

the average velocity will be $\frac{x}{t}=\frac{5Km}{5hour}=1km/h$ or $1KMph$