Question

A person walks ${25}^o$ north of east for 3.18 km. How far would she have to walk due north and then due east to arrive at the same location?

• A. toward north 2.88km and toward east 1.34 km.
• B. toward north 2.11 km and toward east 2.11 km.
• C. toward north 1.25 km and toward east 1.93 km.
• D. toward north 1.34 km and toward east 2.88 km.

Answer 1

The correct option is D toward north 1.34 km and toward east 2.88 km.

Distance she has to walk due north $S_N=3.18\sin {25}^o$

$\therefore S_N=3.18\times 0.422=1.34km$

Distance she has to walk due east $S_E=3.18\cos {25}^o$

$\therefore S_E=3.18\times 0.906=2.88km$