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Question

A person walks up a stationary escalation in t1 second. If he remains stationary on the escalator, then it can take him up in t2 second. If the length of the escalator is L, then
a. Determine the speed of man with respect to the escalator.
b. Determine the speed of the escalator.
c. How much time would it take him to walk up the moving escalator?

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Solution

a. As the escalator is stationary, so the distance covered in t1 seconds is L which is the length of the escalator.
Speed of man w.r.t. the escalator, vme=Lt1

b.When the man is stationary, by taking man as a reference point the distance covered by escalator is L in time t2.
Speed of escalator, vc=Lt2

c. Speed of man w.r.t. the ground, vm=vme+vc_
vm=Lt1+Lt2
=L[1t1+1t1]= L[t1+t2t1t2]
t=Lvm=[t1t2t1+t2]
which is the time taken by the man to walk up the moving escalator.

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