A person wanted to sell a scooter at a loss of 25%. But at the last moment, he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP's is ₹4000, then find the CP of the scooter.

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Solution

Let cost price of the scooter be ₹ x.
If he sells the scooter at a loss of 25%, then
$S P = x - 25 % o f x = x - \frac{25}{100} x$ = ₹ $\frac{75}{100}$ x
and if he sells the scooter at a loss of 20 %, then
$S P = x - 20 % o f x = x - \frac{20}{100} x = \frac{80}{100} x$
It is given that the difference in the two SP's is ₹ 4000.
$∴ \frac{80}{100} x - \frac{75}{100} x = 4000 \Rightarrow \frac{80 x - 75 x}{100} = 4000 \Rightarrow \frac{5 x}{100} = ₹ 4000 \Rightarrow x = \frac{4000 \times 100}{5}$
= ₹ 80000
Hence, cost price of scooter is ₹ 80000.

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