Question

A person weighs $110.84N$ on the moon whose acceleration due to gravity is one-sixth of that earth if the value of g on earth is $9.8m{s}^{-2}$ calculate, acceleration due to gravity on the earth.

• A. $1.89m{s}^{-2}$
• B. $1.63m{s}^{-2}$
• C. $2.89m{s}^{-2}$
• D. $2.63m{s}^{-2}$

Answer 1

Answer: (A)

$1.89m{s}^{-2}$

According to the question acceleration due to gravity on the moon is one sixth of the earth.

Acceleration due to gravity on earth-

$g_e=9.8m{s}^{-2}$

So, acceleration due to gravity on the moon is,

$g_m=\frac{g_e}{6}$

$\Rightarrow g_m=\frac{9.8}{6}$

$\Rightarrow g_m=1.63m{s}^{-2}$