Question

A person weighs 60 kg. The area under the foot of the person is $180c{m}^2$. Find the pressure exerted on the ground by the person. (Take $g=9.8m{s}^{-2})$.

• A. $32.6\times {10}^{2}Pa$
• B. $32.6\times {10}^{3}Pa$
• C. $32.6\times {10}^{4}Pa$
• D. $32.6\times {10}^{5}Pa$

Answer 1

The correct option is B $32.6\times {10}^{3}Pa$

$Force,F=60kgwt=60\times 9.8N$
$=60\times \frac{98}{10}=6\times 98N$
Area under the foot (A) $=180c{m}^2$
$\frac{180}{10000}{m}^2$
$\therefore P=\frac{F}{A}$
$=\frac{6\times 98\times 10000}{180}Pa=\frac{98}{3}\times {10}^{3}Pa$
$=32.6\times {10}^{3}Pa$