A person with a defective eye is unable to see objects nearer than 1 m. He wants to see an object at a distance of 60 cm. The focal length of the lens needed to correct his defect will be

100 cm

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150 cm

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- 150 cm

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60 cm

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Solution

The correct option is B $150 cm$
$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

$= \frac{1}{- 100} - \frac{1}{- 60}$

$= \frac{1}{150}$

$∴ f = 150 cm$

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A person with a defective eye is unable to see objects nearer than 1 m. He wants to see an object at a distance of 60 cm. The focal length of the lens needed to correct his defect will be

The correct option is B 150 cm1f=1v−1u =1−100−1−60 =1150 ∴f=150 cm

The correct option is B $150 cm$
$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

$= \frac{1}{- 100} - \frac{1}{- 60}$

$= \frac{1}{150}$

$∴ f = 150 cm$