A petrol tank is a cylinder of base diameter 21 cm and length 18 cm fitted with conical ends each of axis length 9 cm.Determine the capacity of the tank.

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Solution

Volume of the cylindrical portion of the tank

$= π r^{2} h$

$= \frac{22}{7} \times (\frac{21}{2})^{2} \times 18 = \frac{174636}{28} = 6237 c m^{3}$

Volume of 2 conical ends

$= 2 \times \frac{1}{3} π r^{2} l$

$= \frac{2}{3} \times \frac{22}{7} \times (\frac{21}{2})^{2} \times 9 = 2079 c m^{3}$

Therefore, capacity of the tank $= 6237 + 2079 = 8316 c m^{3}$

Thus, capacity of the tank= $8316 c m^{3}$

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A petrol tank is a cylinder of base diameter 21 cm and length 18 cm fitted with conical ends each of axis length 9 cm.Determine the capacity of the tank.

Volume of the cylindrical portion of the tank =πr2h =227×(212)2×18=17463628=6237 cm3 Volume of 2 conical ends =2×13πr2l =23×227×(212)2×9=2079 cm3 Therefore, capacity of the tank=6237+2079=8316 cm3 Thus, capacity of the tank=8316 cm3