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Byju's Answer
Standard VIII
Mathematics
Applications (Word Problem)
A pharmacist ...
Question
A pharmacist needs to strengthen a
10
%
alcohol solution to one of
20
%
alcohol.How much pure alcohol should be added to
400
ml of
10
%
solution?
Open in App
Solution
Let
x
ml of pure alcohol be added to
400
ml of
10
%
solution to convert, it into
20
%
alcohol.
In
10
%
alcohol,pure alcohol in
400
ml
=
400
×
10
100
=
40
ml
To be added in the solution of
400
ml
=
x
ml
In
20
%
alcohol,pure alcohol in
400
+
x
ml
=
(
400
+
x
)
×
20
100
⇒
40
+
x
=
(
400
+
x
)
×
20
100
⇒
40
+
x
=
(
400
+
x
)
5
⇒
200
+
5
x
=
400
+
x
⇒
5
x
−
x
=
400
−
200
⇒
4
x
=
200
⇒
x
=
200
4
=
50
ml
Pure alcohol to be added is
50
ml
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