A ϕ25mm hole is pierced in a t=2.5mm thick steel sheet having shear strength τ=350MPa. If the diametral clearance is given by the expression c=0.0064√τ, the die diameter (in mm), punch diameter (in mm) and punch force in (kN) respectively are
A
25.0,25.3,171.8
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B
25.0,24.7,68.75
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C
24.7,25.0,171.8
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D
25.3,25.0,68.75
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Solution
The correct option is D25.3,25.0,68.75 Given, t=2.5mm,τ=350MPa dhole=25mm
Punch dia = Dia of hole =25mm
Diametral clearance =0.0064× 2.5 ×√350 =0.299≈0.3mm
Die dia = Punch dia + Clearance
=25+0.3=25.3mm
Punch force =πdtτ=π×25×2.5×350 =68.72kN