A photo-cell is illuminated by a source of light placed at distance d from cell. Graph of photo current I vs. d is best represented by

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Solution

The correct option is A
Photo current depends on No. of electrons ejected 'N' and N $\propto$ Intensity of light where, Intensity $= \frac{P o w e r}{A r e a} = \frac{P}{4 π d^{2}}$

So $I \propto \frac{P}{4 π d^{2}} \Rightarrow I \propto \frac{1}{d^{2}}$

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A photo-cell is illuminated by a source of light placed at distance d from cell. Graph of photo current I vs. d is best represented by

The correct option is A Photo current depends on No. of electrons ejected 'N' and N ∝ Intensity of light where, Intensity =PowerArea=P4πd2 So I∝P4πd2⇒I∝1d2

The correct option is A
Photo current depends on No. of electrons ejected 'N' and N $\propto$ Intensity of light where, Intensity $= \frac{P o w e r}{A r e a} = \frac{P}{4 π d^{2}}$

So $I \propto \frac{P}{4 π d^{2}} \Rightarrow I \propto \frac{1}{d^{2}}$