Question

A photo diode is made from a semiconductor ${In}_{0.53}$. As, with $E_g$=0.73 eV. What is the maximum wavelength which it can detect? $h=6.63\times {10}^{-34}{J}_s$.

Answer 1

The maximum wavelength $\left(\lambda \right)$, which a photo-diode can detect corresponds to the energy

$E_g,So\frac{h_c}{\lambda }=E_g$

$or\lambda =\frac{h_c}{E_g}=\frac{6.63\times {10}^{-34}\times (3\times {10}^8)}{0.73\times 1.6\times {10}^{-19}}$

$=1703\times {10}^{-9}m=1703nm$