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A photoelectric surface is illuminated successively by monochromatic light of wavelengths λ and λ2. If the maximum kinetic energy of the emitted photoelectrons in the second case is 3 times that in the first case, the work function of the surface of the material is
(h = Planck's constant, c = speed of light)

A
hc2λ
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B
hcλ
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C
hc3λ
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D
3hcλ
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Solution

The correct option is A hc2λ
Let ϕ be the work function.
We know kinetic energy for emitted electrons,
K.Eλ=hcλϕ
K.Eλ/2=hcλ/2ϕ
K.Eλ/2=3(K.Eλ)................(1)Substituting values in (1), we get
ϕ=hc2λ

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