A photographic plate records sufficiently intense image when exposed with $10$ $W$ source for 12 s. How much time it will take if exposed with $12$ $W$ source:

12

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10

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8

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9

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Solution

The correct option is A $10$ s
The product power and time is always constant, So..
$P_{1} t_{1}$ = $P_{2} t_{2}$
or $t_{2}$ = $\frac{12 \times 10}{12}$ = $10$ s

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A photographic plate records sufficiently intense image when exposed with 10 W source for 12 s. How much time it will take if exposed with 12 W source:

The correct option is A 10 sThe product power and time is always constant, So..P1t1 = P2t2 or t2 = 12×1012 = 10 s

A photographic plate records sufficiently intense image when exposed with $10$ $W$ source for 12 s. How much time it will take if exposed with $12$ $W$ source:

The correct option is A $10$ s
The product power and time is always constant, So..
$P_{1} t_{1}$ = $P_{2} t_{2}$
or $t_{2}$ = $\frac{12 \times 10}{12}$ = $10$ s