A photon creates a pair of electron-positron with equal kinetic energy. Let kinetic energy of each particle is 0.29 MeV. Then what should be energy of the photon

1.60 MeV

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1.63 MeV

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2.0 MeV

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1.90 MeV

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Solution

The correct option is B 1.60 MeV
The minimum energy of photon for pair production $= 0.51 M e v$
Total $= 2 \times 0.51 M e v = 1.02$
K.E of each = 0.29
$T o t a l K E = 2 \times 0.29$
Total energy of photon $= 1.02 + 0.58 = 1.6 M e v$

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A photon creates a pair of electron-positron with equal kinetic energy. Let kinetic energy of each particle is 0.29 MeV. Then what should be energy of the photon

The correct option is B 1.60 MeVThe minimum energy of photon for pair production =0.51MevTotal =2×0.51Mev=1.02K.E of each = 0.29TotalKE=2×0.29Total energy of photon =1.02+0.58=1.6Mev

The correct option is B 1.60 MeV
The minimum energy of photon for pair production $= 0.51 M e v$
Total $= 2 \times 0.51 M e v = 1.02$
K.E of each = 0.29
$T o t a l K E = 2 \times 0.29$
Total energy of photon $= 1.02 + 0.58 = 1.6 M e v$