Question

A photon of energy 12.09eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of the excited state is

• A. 4
• B. 5
• C. 3
• D. 2

Answer 1

Answer: (D)

3

energy in excited state = -13.6+12.09 = -1.51 eV

$-\frac{13.6}{n_2^2}=-1.51$

$n_2=3$