A photon of energy 3.4 eV is incident on a metal having work function 2 eV. The maximum K.E. of photo-electrons is equal to

1.4 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.7 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.4 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.8 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1.4 eV
$K_{m a x} = (E - W_{0}) = (3.4 - 2) e V = 1.4 e V$

Suggest Corrections

Similar questions

3.4 e V

2 e V

6 e V

4 e V

K E

1 e V

2.5 e V

0.5 e V

Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV. The minimum kinetic energy of the emitted photo-electrons will be

Join BYJU'S Learning Program