A photon of light with wavelength $6000 ˚ A$ has an energy $E$ . Calculate the wavelength of photon of a light which corresponds to an energy equal to $2 E$ .

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Solution

$h \times x = 12420 e V / A^{\circ} E = \frac{h c}{λ} = \frac{12420}{6000} = 2.07 e V$
The wavelength of light have energy $2 E = 4.14 e V$
$4.14 = \frac{12420}{λ (A^{\circ})} λ = 3000 A^{\circ}$

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A photon of light with wavelength 6000˚A has an energy E. Calculate the wavelength of photon of a light which corresponds to an energy equal to 2E.

h×x=12420eV/A∘E=hcλ=124206000=2.07eVThe wavelength of light have energy 2E=4.14eV4.14=12420λ(A∘)λ=3000A∘

A photon of light with wavelength $6000 ˚ A$ has an energy $E$ . Calculate the wavelength of photon of a light which corresponds to an energy equal to $2 E$ .

$h \times x = 12420 e V / A^{\circ} E = \frac{h c}{λ} = \frac{12420}{6000} = 2.07 e V$
The wavelength of light have energy $2 E = 4.14 e V$
$4.14 = \frac{12420}{λ (A^{\circ})} λ = 3000 A^{\circ}$