A photon of radiation of wavelength 600 nm has energy E . The wavelength of photon of radiation having energy 0.25E is

600nm

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2400 nm

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150 nm

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300 nm

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Solution

The correct option is B 2400 nm
$\frac{E_{1}}{E_{2}} = \frac{λ_{2}}{λ_{1}} \frac{E}{0} .25 E = \frac{λ_{2}}{600}, λ_{2} = 2400 n m$

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