A photon of wavelength $100 A^{0}$ has energy 12.3 eV. If the wavelength $500 A^{0}$ having intensity I falls on a metal surface, the saturation current is $0.40 μ A$ and stopping potential is 1.36 V. The work function of the metal is

2.47 eV

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1.36 eV

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1.10 eV

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0.43 eV

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Solution

The correct option is C 1.10 eV
Energy, $E = \frac{h c}{λ} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{500 \times 10^{- 10}} J = 2.46 e V$
Now, for stopping potential:
$V_{\circ}$ =stopping potential
$V_{\circ} = \frac{h}{c} (ϑ - ϑ_{\circ}) e V_{\circ} = h ϑ - h ϑ_{\circ} h ϑ_{\circ} = W = h ϑ - V_{\circ} = 2.46 e V - 1.36 e V = 1.10 e V$

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A photon of wavelength 100A0 has energy 12.3 eV. If the wavelength 500A0 having intensity I falls on a metal surface, the saturation current is 0.40μA and stopping potential is 1.36 V. The work function of the metal is

The correct option is C 1.10 eVEnergy,E=hcλ=6.6×10−34×3×108500×10−10J=2.46eVNow, for stopping potential:V∘=stopping potentialV∘=hc(ϑ−ϑ∘)eV∘=hϑ−hϑ∘hϑ∘=W=hϑ−V∘=2.46eV−1.36eV=1.10eV

A photon of wavelength $100 A^{0}$ has energy 12.3 eV. If the wavelength $500 A^{0}$ having intensity I falls on a metal surface, the saturation current is $0.40 μ A$ and stopping potential is 1.36 V. The work function of the metal is