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Question

A physical quantity P is related to four observables a, b, c and d as follows : P = a³ b ²/ (√c d) The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2%, respectively. What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ?

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Solution

Given, the percentage errors in the measurement of four observables a, b, c and d are 1%, 3%, 4% and 2% respectively and the calculated value of P is 3.763.

The relation between the P and four observables a, b, c and d is,

P= a 3 b 2 c d

Differentiate the above expression,

ΔP P = 3Δa a + 2Δb b + Δc 2c + Δd d

Take the percentage in both side of the equation.

( ΔP P ×100 )%=( 3Δa a ×100+ 2Δb b ×100+ Δc 2c ×100+ Δd d ×100 )% =( 3×1+2×3+ 1 2 ×4+2 ) =13%

Thus, the percentage error in quantity P is 13%.

The percentage error in the physical quantity P is,

( ΔP P ×100 )%=13% ΔP= 13P 100

Substitute the given value in the above expression.

ΔP= 13×3.763 100 =0.48919

Since the error comes out up-to first decimal place, so the calculated value of P must be round off up-to first decimal place. Thus, calculated value of P after rounding off is 3.8.


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