A physical quantity X is expressed as velocity - X - density - The dimensions of X areA- - ML 2 T -2-B- - ML -1 T -2-C- - ML 2 T -1-D- - MLT -1-

The correct option is B [ML^ 1T^ 2]From the given expression nbsp; Velocity =√((Xdensity)), we can say that [X]=[(velocity)^2density] ⇒ [X]=[(LT^ 1)^2(ML^ 3 ...

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Standard XII

Physics

Units and Dimensions

A physical qu...

Question

A physical quantity $X$ is expressed as velocity $= \sqrt{(\frac{X}{density})}$ . The dimensions of $X$ are

[M L T^{- 1}]

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[M L^{2} T^{- 2}]

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[M L^{- 1} T^{- 2}]

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[M L^{2} T^{- 1}]

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Solution

The correct option is C $[M L^{- 1} T^{- 2}]$
From the given expression
Velocity $= \sqrt{(\frac{X}{density})}$ ,
we can say that
$[X] = [(velocity)^{2} density]$
$\Rightarrow [X] = [(L T^{- 1})^{2} (M L^{- 3})] = [M L^{- 1} T^{- 2}]$

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A physical quantity X is expressed as velocity =√(Xdensity). The dimensions of X are

The correct option is C [ML−1T−2]From the given expression Velocity =√(Xdensity), we can say that [X]=[(velocity)2density] ⇒ [X]=[(LT−1)2(ML−3)]=[ML−1T−2]

A physical quantity $X$ is expressed as velocity $= \sqrt{(\frac{X}{density})}$ . The dimensions of $X$ are

The correct option is C $[M L^{- 1} T^{- 2}]$
From the given expression
Velocity $= \sqrt{(\frac{X}{density})}$ ,
we can say that
$[X] = [(velocity)^{2} density]$
$\Rightarrow [X] = [(L T^{- 1})^{2} (M L^{- 3})] = [M L^{- 1} T^{- 2}]$