CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A physics student is performing a experiment in which she twirls rubber stopper at the end of a string around in a circle at nearly constant speed and tries to determine its acceleration. Which of the following single changes would enables her to most nearly double the acceleration of the rubber stopper?

A
Double the speed of the rubber stopper.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Use a string that is twice as long as the original string.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Reduce the speed of the rubber stopper to half its original value.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Use a string that is half as long as the original string
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
E
Use a rubber stopper with twice as much mass as the original rubber stopper.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is E Use a string that is half as long as the original string
Due to constant speed , student is doing uniform circular motion so tangential acceleration is zero .
as the tangential acceleration is zero , therefore total acceleration will be equal to centripetal acceleration , which is
a=v2/r
which can be doubled by using a string that is half as long as the original string .
a=v2r2=2a

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circular Motion: A Need for Speed
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon