Question

A $\pi$-bond is formed by the overlap of:

• A. $s-s$ orbitals
• B. $s-p$ orbitals
• C. $p-p$ orbitals in end to end manner
• D. none of the above

Answer 1

The correct option is D none of the above

$\pi$ bonds are formed by the sideways or lateral overlapping of $p$ orbitals. Whereas, $\sigma$ bonds are formed by axial (or end to end) overlapping of atomic orbitals. In the below diagram, lateral overlapping of $\pi$ bonds is explained.