CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A piano-convex lens (refractive index μ1) fits exactly into a piano-concave lens (refractive index μ2). Their plane surfaces are parallel to each other. R is the radius of curvature of the curved surface of the lenses, then focal length of the combination is:

A
Rμ1μ2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2Rμ2μ1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
R2(μ1μ2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D none of these
1r=μ11R+1μ2R=(μ1+μ2)2R

f=R(μ1+μ2)2, Hence none of them are correct

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Power and Thin Lenses in Contact
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon