A picture frame has outer dimensions -24cm- 28cm and inner dimensions 16cm- 20cm - Find the are of each section of the frame - if the width of each section is same -

[ According to question,; The #160; width #160; of #160; each #160; section #160; is ...

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Standard VI

Mathematics

Area of Square

A picture fra...

Question

A picture frame has outer dimensions $= 24 c m \times 28 c m$ and inner dimensions $16 c m \times 20 c m$ . Find the are of each section of the frame , if the width of each section is same .

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Solution

$\begin{matrix} A c c o r d i n g t o q u e s t i o n, T h e w i d t h o f e a c h s e c t i o n i s s a m e : I B = B J = C K = C L = D M = D N = A O = A P N o w, I L = I B + B C + C L 28 c m = I B + 20 + C L I B + C L = 8 c m a n d, I B = C L = 4 c m h e n c e, I B = B J = C K = C L = D M = D N = A O = A P = 4 c m i f, t h e A r e a o f sec t i o n B E F C = t h e A r e a o f sec t i o n D G H A = = [\frac{1}{2} (20 + 28) (4)] c m^{2} = 96 c m^{2} s o t h a t t h e A r e a o f sec t i o n A B E H = t h e A r e a o f sec t i o n C D G F i s s a m e . \end{matrix}$

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Q. Question 11
Diagram of the adjacent picture frame has outer dimensions = 24 cm

\times

28 cm and inner dimensions 16 cm

\times

20 cm. Find the area of each section of the frame, if the width of each section is same.

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A picture frame has outer dimensions =24cm×28cm and inner dimensions 16cm×20cm . Find the are of each section of the frame , if the width of each section is same .

Accordingtoquestion,Thewidthofeachsectionissame:IB=BJ=CK=CL=DM=DN=AO=APNow,IL=IB+BC+CL28cm=IB+20+CLIB+CL=8cmand,IB=CL=4cmhence,IB=BJ=CK=CL=DM=DN=AO=AP=4cmif,theAreaofsectionBEFC=theAreaofsectionDGHA==[12(20+28)(4)]cm2=96cm2sothattheAreaofsectionABEH=theAreaofsectionCDGFissame.

A picture frame has outer dimensions $= 24 c m \times 28 c m$ and inner dimensions $16 c m \times 20 c m$ . Find the are of each section of the frame , if the width of each section is same .