A picture is $7 \frac{3}{5} c m$ wide. How much should it be trimmed to fit in a frame $7 \frac{3}{10} c m$ wide?

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Solution

Actual width of the picture = $7 \frac{3}{5} c m$ = $\frac{38}{5} c m$
Required width of the picture = $7 \frac{3}{10} c m = \frac{73}{10} c m$
∴ Extra width = $\frac{38}{5} - \frac{73}{10} c m$
$= \frac{76 - 73}{10} c m$ [∵ LCM of 5 and 10 is 10]
$= \frac{3}{10} c m$
Hence, the width of the picture should be trimmed by $\frac{3}{10} c m$ .

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A picture is 735 cm wide. How much should it be trimmed to fit in a frame 7310 cm wide?

Actual width of the picture =735 cm=385 cmRequired width of the picture =7310 cm=7310 cm∴ Extra width =385−7310 cm =76−7310 cm [∵ LCM of 5 and 10 is 10] =310 cmHence, the width of the picture should be trimmed by 310 cm.

A picture is $7 \frac{3}{5} c m$ wide. How much should it be trimmed to fit in a frame $7 \frac{3}{10} c m$ wide?