A piece of aluminum of volume 200 cm³and density 2.7g/cm³is completely immersed in kerosene. Determine the up thrust exerted on the piece of aluminum and also determine how much it will in kerosene. Explain the steps with reasons.

Open in App

Solution

Thrust exerted = Weight of Volume of liquid displaced by aluminium = density of liquid x g x Volume of solid = 200 x 10^-6 x 9.81 x 810 = 1.56 Newton.....the piece of aluminium will completely sink in kerosene as its density is greater than liquid

Suggest Corrections

Similar questions

1.00 k g

2700 k g / m^{3}

(a)

(b)

g = 10 m / s^{2}

= 10^{3} k g m^{- 3}

7800 k g / m^{3}

100 c m^{3}

g = 10 m / s^{2}

A body when immersed in kerosene, it sinks. What relation could be established between the density of the body and density of kerosene?

A body when immersed in kerosene, it sinks. What is the relationship between the densities of body and kerosene?

Join BYJU'S Learning Program