Question

A piece of charcoal from the ruins of a settlement in Japan was found to have $C^{14}/C^{12}$ ratio that was 0.617 times that found in living organisms. $t_{1/2}$ for ${}^{14}C$ is 5770 yr. The age of this piece of charcoal is :

• A. 3042.54 year
• B. 4021.29 year
• C. 5125.42 year
• D. None of these

Answer 1

The correct option is B 4021.29 year

As we know, $t=\frac{2.303}{\lambda }log\left(\frac{N_o}{N}\right)$

$=2.303\times \frac{t_{1/2}}{0.693}log\left(\frac{N_o}{0.617N_o}\right)=$ 4021 years