A piece of cork is floating in water in a small tank. The cork oscillates up and down vertically when small ripples pass over the surface of the water. The velocity of the ripples being $0.21 m s^{- 1}$ , wavelength 15 mm and amplitude 5 mm, find the maximum velocity of the piece of cork $(π = \frac{22}{7})$ .

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Solution

Maximum velocity is given by the formula
$ω A = 2 π υ A$
$= \frac{2 \times 22 \times 0.21 \times 15}{7 \times 5} m s^{- 1}$
$= 0.44 m s^{- 1}$

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A piece of cork is floating in water in a small tank. The cork oscillates up and down vertically when small ripples pass over the surface of the water. The velocity of the ripples being 0.21ms−1, wavelength 15 mm and amplitude 5 mm, find the maximum velocity of the piece of cork (π=227).

Maximum velocity is given by the formulaωA=2πυA=2×22×0.21×157×5ms−1=0.44ms−1

Maximum velocity is given by the formula
$ω A = 2 π υ A$
$= \frac{2 \times 22 \times 0.21 \times 15}{7 \times 5} m s^{- 1}$
$= 0.44 m s^{- 1}$