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Question

A piece of equipment cost a certain factory Rs.6,00,000. If it depreciates in value, 15% the first, 13.5% the next year, 12% the third year, and so on. What will be its value at the end of 10 years, all percentages applying to the original cost?

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Solution

The piece of equipment depreciates 15% in first year i.e., 15100×600,000=Rs. 90,000

Value depreciated in 1st year =Rs.90,000

The equipment depreciates at the rate 13.5% in 2nd year i.e. 1351000×600,000=Rs.81000

Value depreciated in 2st year =Rs.81,000

The value after 3rd year =12100×600000

Value depreciated in 3rd year =Rs.72000

The the series of depreciation become 90,000,81,000,72,000... with,

a=90,000 and d=9000

The total depreciation in 10 years

S10=102[2×90000+(9)(9000)]

=5[18000081000]

=5[99000] [UsingSn=n2[2a+(n1)d]]

=Rs.495,000

The cost of machine after 10 years

=600,000495,000=Rs.105,000


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