A piece of granulated zinc was dropped into copper sulphate solution. After some time, the colour of the solution changed from :
(1) light green to blue
(2) blue to colourless
(3) light green to colourless
(4) bule to yellow

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Solution

Zinc is more reactive than copper, as zinc displaces copper from the copper sulphate and form zinc sulphate, as a result, the blue colour solution turns colourless.
$Zn (s) + {CuSO}_{4} (aq) \to {ZnSO}_{4} (aq) + Cu (s)$

Hence, the correct answer is option 2.

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Q. Aluminium sulphate and copper sulphate solutions were taken in two test tubes I and II respectively. Iron filings were then added to both the solutions. The four students A, B, C and D recorded their observations in the form of a table as given below.

Student	Aluminium sulphate solution (I)	Copper sulphate solution (II)
A	Colourless changes to light green	Blue colour of the solution is retained
B	Colour of colourless solution does not change	Blue colour of the solution changes to light green
C	Colourless solution changes to light blue	Blue colour of the solution changes to colourless
D	Colour of colourless solution remains unchanged	Blue colour of the solution fades away

The correct set of observations have been recorded by the students :
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(2) B
(3) C
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A piece of granulated zinc was dropped into copper sulphate solution. After some time, the colour of the solution changed from : (1) light green to blue (2) blue to colourless (3) light green to colourless (4) bule to yellow

Zinc is more reactive than copper, as zinc displaces copper from the copper sulphate and form zinc sulphate, as a result, the blue colour solution turns colourless. Zn(s)+CuSO4(aq)→ZnSO4(aq)+Cu(s) Hence, the correct answer is option 2.

A piece of granulated zinc was dropped into copper sulphate solution. After some time, the colour of the solution changed from :
(1) light green to blue
(2) blue to colourless
(3) light green to colourless
(4) bule to yellow

Zinc is more reactive than copper, as zinc displaces copper from the copper sulphate and form zinc sulphate, as a result, the blue colour solution turns colourless.
$Zn (s) + {CuSO}_{4} (aq) \to {ZnSO}_{4} (aq) + Cu (s)$

Hence, the correct answer is option 2.