Question

A piece of ice of mass 40 g is dropped into 200 g of water at 50${}^{\circ }C$. Calculate the final temperature of the water after all the ice has melted. (Specific heat capacity of water = 4200 J/kg ${}^{\circ }C$, specific latent heat of fusion of ice $=336\times {10}^3$​ J/kg)

• A. 18 ⁰C
• B. 20.5 ⁰C
• C. 30 ⁰C
• D. 28.3 ⁰C

Answer 1

The correct option is D

28.3 ⁰C

Heat gained by ice = Heat loss by water

\(m L + mst_1 = m s t\)

$(40\times 336)+(40\times 4.2x)=200\times 4.2\times (50–x)x$

x = 28.3${}^{\circ }C$