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Question

A piece of iron of mass 0.05kg is heated to a temperature of 200C and dropped into a beaker containing 0.4kg of water at 20C. If the final temperature of water and iron is 22.4C, find the specific heat capacity of iron.

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Solution

By the energy conservation, thermal energy lost by hot iron = thermal energy gained by cold water
If Tf be the final temperature of mixture, miSi(TiTf)=mwSw(TfTw) where Si= specific of iron and Sw=4180J/kgoC, specific of water.

or Si=mwSw(TfTw)mi(TiTf)=(0.4)(4180)[(22.420)]0.05(20022.4)=4012.88.88=451.89J/kgoC

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