A piece of iron of mass $2.0$ kg has a thermal capacity of $966 J K^{- 1}$ . Find heat energy needed to warm it by $15^{\circ} C$

14.490 J

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7245 J

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14490 J

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28980 J

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Solution

The correct option is C 14490 J
Amount of heat energy required $=$ Thermal capacity $\times$ (Temperature increase)
$= 966 \times (15) = 14490 J$

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A piece of iron of mass 2.0 kg has a thermal capacity of 966 JK−1. Find heat energy needed to warm it by 15∘C

The correct option is C 14490 JAmount of heat energy required = Thermal capacity × (Temperature increase) =966×(15)=14490 J

A piece of iron of mass $2.0$ kg has a thermal capacity of $966 J K^{- 1}$ . Find heat energy needed to warm it by $15^{\circ} C$

The correct option is C 14490 J
Amount of heat energy required $=$ Thermal capacity $\times$ (Temperature increase)
$= 966 \times (15) = 14490 J$