Question

A piece of iron weighing $15g$ is dropped into a cavity in a block of ice at $0^{o}C$. $2.5g$ of ice are melted. If the temperature of iron was ${113.6}^{o}C$, calculate the sp. Heat of iron. ($L$ for fusion of ice $=80cal/g$

Answer 1

Given: A piece of iron weighing 15g is dropped into a cavity in a block of ice at $0^{o}C$. 2.5g of ice are melted. If the temperature of iron was ${113.6}^{o}C$,

To find the specific heat of iron.

Solution:

As per the given criteria,

Mass of the iron piece, $m_b=15g$

Temperature of the iron piece, $T_b={113.6}^{\circ }C$

Mass of melted ice, $m_i=2.5g$

Latent heat of ice, $L=80cal/g$

Let specific heat of the iron be $c_b$

As the block does not melt completely therefore final temperature is zero degree Celsius.

Heat gained by ice to melt $=m_{i}L=2.5\times 80=200cal$

Heat lost by iron piece $=m_b{c}_b{T}_b=15\times c_b\times 113.6=1704c_b$

We know,

Heat gained = heat lost

Therefore, $200=1704c_b⟹c_b=\frac{200}{1704}=0.117cal/g$

is the specific heat of the iron.