A piece of lead weighs 100g in water.If density of lead is 11g/cm3 then weight of the piece of lead in air is?

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Solution

V = mass/density

V = 100/11 cm^3

we know that density of air is 1.225 kg/m^3

so,
mass of lead in the air

M = (100/11)/(1000000)×1.225

M = 0.0111 gm

Hope this help you

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A piece of lead weighs 100g in water.If density of lead is 11g/cm3 then weight of the piece of lead in air is?

V = mass/density V = 100/11 cm^3 we know that density of air is 1.225 kg/m^3 so, mass of lead in the air M = (100/11)/(1000000)×1.225 M = 0.0111 gm Hope this help you

V = mass/density

V = 100/11 cm^3

we know that density of air is 1.225 kg/m^3

so,
mass of lead in the air

M = (100/11)/(1000000)×1.225

M = 0.0111 gm

Hope this help you