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Byju's Answer

Standard XII

Chemistry

Molar and Specific Heat Capacity

A piece of me...

Question

A piece of metal weighing $100$ g is heated to $80^{o}$ C and dropped into $1$ kg of cold water in an insulated container at $15^{o}$ C. If the final temperature of the water in the container is ${15.69}^{o}$ C, the specific heat of the metal in $J / g^{o}$ .C is:

0.38

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0.24

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0.45

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0.13

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Solution

The correct option is C $0.45$
Heat exchanged is given by,
$Q = m \times s \times (T_{2} - T_{1})$ where $s =$ specific heat

So, when heated metal is dropped into the cold water, we can write:

$m_{m e t a l} \times s_{m e t a l} \times (T_{2} - T_{1})_{m e t a l} = m_{w a t e r} \times s_{w a t e r} \times (T_{2} - T_{1})_{w a t e r}$

$0.1 \times s_{m e t a l} \times (80 - 15.69) = 1 \times 4.18 \times (15.69 - 15)$

$s_{m e t a l} = 0.45 J / g^{0} C$

Hence, option C is correct.

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A piece of metal weighing 100 g is heated to 80o C and dropped into 1 kg of cold water in an insulated container at 15o C. If the final temperature of the water in the container is 15.69o C, the specific heat of the metal in J/go.C is:

A piece of metal weighing $100$ g is heated to $80^{o}$ C and dropped into $1$ kg of cold water in an insulated container at $15^{o}$ C. If the final temperature of the water in the container is ${15.69}^{o}$ C, the specific heat of the metal in $J / g^{o}$ .C is: