Question

A piece of steel has a volume of 12 cm${}^3$ and a mass of 96 g. Find its density in kg/m${}^3$.

Density $=x\times {10}^{3}kg/m^3$. What is the value of $x$?

• A. 9
• B. 10
• C. 11
• D. 8

Answer 1

Answer: (D)

8

We have, $1c{m}^3={10}^{-6}{m}^3$

So, $12c{m}^3=12\times {10}^{-6}{m}^3$

Again, $1g={10}^{-3}kg$

So, $96g=96\times {10}^{-3}kg$

Therefore, density $=\frac{mass}{volume}=\frac{96\times {10}^{-3}}{12\times {10}^{-6}}=8\times {10}^{3}kg/m^3$

Hence option D is the correct answer.