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Standard VIII

Mathematics

Applications (Word Problem)

A piece of st...

Question

A piece of string is $40$ centimeters long. It is cut into three pieces. The longest piece is $3$ times as long as the middle-sized and the shortest piece is $23$ centimeters shorter than the longest piece. Find the length of the shortest piece(in cm).

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Solution

The correct option is D $4$
Let the length of largest piece be $3 x$ .

Thus length of middle sized part will be $x$ .

According to the given condition, length of shortest part is $3 x - 23$ .

Or, $3 x + x + (3 x - 23) = 40.$
$7 x = 63$

Or, $x = 9$

Or, the shortest piece $= 3 (9) - 23 = 4$

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A piece of string is 40 centimeters long. It is cut into three pieces. The longest piece is 3 times as long as the middle-sized and the shortest piece is 23 centimeters shorter than the longest piece. Find the length of the shortest piece(in cm).

The correct option is D 4Let the length of largest piece be 3x. Thus length of middle sized part will be x. According to the given condition, length of shortest part is 3x–23. Or, 3x+x+(3x–23)=40.7x=63 Or, x=9 Or, the shortest piece =3(9)–23=4

A piece of string is $40$ centimeters long. It is cut into three pieces. The longest piece is $3$ times as long as the middle-sized and the shortest piece is $23$ centimeters shorter than the longest piece. Find the length of the shortest piece(in cm).

The correct option is D $4$
Let the length of largest piece be $3 x$ .

Thus length of middle sized part will be $x$ .

According to the given condition, length of shortest part is $3 x - 23$ .

Or, $3 x + x + (3 x - 23) = 40.$
$7 x = 63$

Or, $x = 9$

Or, the shortest piece $= 3 (9) - 23 = 4$