A piece of weighs 44.5gf in air. If the density of iron is 8.9*10^3kg/m^3,find weight of iron piece when immersed in water.

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Solution

Density of water (d) = 10³ kg/m³
Density of iron (d’) = 8.9 × 10³ kg/m³

Weight in water = Weight in air × [1 - d/d’]
= 44.5 kgf × [1 - (10³ kg/m³ / (8.9 × 10³ kg/m³))]
= 39.5 kgf

Weight of iron piece in water is 39.5 kgf

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