Question

A piece of wire carrying a current of $6.00A$ is bent in the form of a circular arc of radius $10.0cm$ , and it subtends an angle of ${120}^o$ at the centre. Find the magnetic field $B$ due to this piece of wire at the centre.

Answer 1

The magnetic field is given as

$B=\frac{{\mu }_{0}i\theta }{4\pi R}$

By substituting the values in the above equation we get

$B=\frac{4\pi \times {10}^{-7}\times 2\pi \times 6}{3\times 4\pi \times 0.1}$

$B=4\pi \times {10}^{-6}$

$B=12.56\times {10}^{-6}T$