CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Introduction to Mensuration

A piece of wi...

Question

A piece of wire of length 108 cm is bent to form a semicircle arc bounded by its diameter. Find its radius and area enclosed.

Open in App

Solution

circumference of semicircle+diameter=total length of wire

πr+2r=108
so r=21

now area of semicircle where r =21
πr^2/2=693

Suggest Corrections

thumbs-up

5

Similar questions

A piece of wire of length 108 cm is bent to form a semicircular arc bounded by its diameter. Find its radius and area enclosed.

$\frac{2 π r}{2} + d = 108$

Area enclosed $= \frac{π r^{2}}{2}$

Q. A piece of wire that has been bent in the form of a semicircle including the bounding diameter is straightened and then bent in the form of a square. The diameter of the semicircle is

14 c m .

Which has a larger area, the semi-circle or the square.

Q. A copper wire when bent in the form of a square encloses an area of

484 c m^{2}

. If the same wire is bent into the form of a circle, find the area enclosed by it.

A magnetised wire of magnetic moment $M$ and length $L$ is bent in the form of a semicircle of radius $r$ . Then its magnetic moment is:

Q. If a copper wire is bend to make a square whose area is

324 {c m}^{2}

. If the same wire is bent to form a semicircle, then find the radius of semicircle.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Basics Revisited

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Introduction to Mensuration

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon