A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R′, then the ratio R′R is:
A
125
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B
15
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C
5
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D
25
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Solution
The correct option is A125 Given the wire is cut into 5 equal parts.
Let the initial resistance of the wire be R
where R=ρlA→R∝l(lengthofthewire)
then, resistance of each one of the five parts =(R5)
Equivalent resistance (R') of resistors connected in parallel is given by 1R′=1R1+1R2..1Rn
Equivalent resistance (R') of five parts connected in parallel is given by: 1R′=1(R5)+1(R5)+1(R5)+1(R5)+1(R5)R′=R25
Therefore, RR′=25
or R′R=125